Team Queue POJ - 2259 （队列）-白红宇

Team Queue POJ - 2259 （队列）

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发布时间：2019-06-08

本文共 3396 字，大约阅读时间需要 11 分钟。

Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for example.

In a team queue each element belongs to a team. If an element enters the queue, it first searches the queue from head to tail to check if some of its teammates (elements of the same team) are already in the queue. If yes, it enters the queue right behind them. If not, it enters the queue at the tail and becomes the new last element (bad luck). Dequeuing is done like in normal queues: elements are processed from head to tail in the order they appear in the team queue.

Your task is to write a program that simulates such a team queue.

Input

The input will contain one or more test cases. Each test case begins with the number of teams t (1<=t<=1000). Then t team descriptions follow, each one consisting of the number of elements belonging to the team and the elements themselves. Elements are integers in the range 0 - 999999. A team may consist of up to 1000 elements.

Finally, a list of commands follows. There are three different kinds of commands:

ENQUEUE x - enter element x into the team queue

DEQUEUE - process the first element and remove it from the queue

STOP - end of test case

The input will be terminated by a value of 0 for t.

Warning: A test case may contain up to 200000 (two hundred thousand) commands, so the implementation of the team queue should be efficient: both enqueing and dequeuing of an element should only take constant time.

Output

For each test case, first print a line saying "Scenario #k", where k is the number of the test case. Then, for each DEQUEUE command, print the element which is dequeued on a single line. Print a blank line after each test case, even after the last one.

Sample Input

23 101 102 1033 201 202 203ENQUEUE 101ENQUEUE 201ENQUEUE 102ENQUEUE 202ENQUEUE 103ENQUEUE 203DEQUEUEDEQUEUEDEQUEUEDEQUEUEDEQUEUEDEQUEUESTOP25 259001 259002 259003 259004 2590056 260001 260002 260003 260004 260005 260006ENQUEUE 259001ENQUEUE 260001ENQUEUE 259002ENQUEUE 259003ENQUEUE 259004ENQUEUE 259005DEQUEUEDEQUEUEENQUEUE 260002ENQUEUE 260003DEQUEUEDEQUEUEDEQUEUEDEQUEUESTOP0

Sample Output

Scenario #1101102103201202203Scenario #2259001259002259003259004259005260001 题意：n个小队，每个小队若干人。入队时，若队伍中已经有了该小队的人就直接排在其后面，没有的话就排在队伍后面。有入队和出队两种操作。 思路：用队列进行模拟，map记录每个人属于哪支队伍，然后que【0】，记录队伍的顺序，que【i】记录该队伍的人。   1 <= i <= 1000

#include
      
       #include
       
        #include
        
         #include
         using namespace std;int t;queue
          
           que[1001];map
           
            mp;int main(){ int cas = 0; while(~scanf("%d",&t) && t) { mp.clear(); for(int i=0;i<=1000;i++) { while(!que[i].empty())que[i].pop(); } int cnt = 0; while(t--) { int k,tmp; scanf("%d",&k); ++cnt; for(int i=1;i<=k;i++) { scanf("%d",&tmp); mp[tmp] = cnt; } } char s[20]; printf("Scenario #%d\n",++cas); while(~scanf("%s",s) && s[0] != 'S') { if(s[0] == 'E') { int tmp; scanf("%d",&tmp); if(que[mp[tmp]].empty())que[0].push(mp[tmp]); que[mp[tmp]].push(tmp); } else { if(!que[0].empty()) { int tmp = que[0].front(); printf("%d\n",que[tmp].front()); que[tmp].pop(); if(que[tmp].empty())que[0].pop(); } } } puts(""); }}

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转载于:https://www.cnblogs.com/iwannabe/p/10632488.html

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